X^2+9x=162

Solution for X^2+9x=162 equation:

X^2+9X=162

We move all terms to the left:

X^2+9X-(162)=0

a = 1; b = 9; c = -162;
Δ = b2-4ac
Δ = 92-4·1·(-162)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*1}=\frac{-36}{2}
=-18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*1}=\frac{18}{2}
=9
$